x=0,4x^2+5

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Solution for x=0,4x^2+5 equation: 



x=0.4x^2+5

We move all terms to the left:

x-(0.4x^2+5)=0

We get rid of parentheses

-0.4x^2+x-5=0

a = -0.4; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-0.4)·(-5)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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